4x^2-8x+4=0.95

Solution for 4x^2-8x+4=0.95 equation:

4x^2-8x+4=0.95

We move all terms to the left:

4x^2-8x+4-(0.95)=0

We add all the numbers together, and all the variables

4x^2-8x+3.05=0

a = 4; b = -8; c = +3.05;
Δ = b2-4ac
Δ = -82-4·4·3.05
Δ = 15.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-\sqrt{15.2}}{2*4}=\frac{8-\sqrt{15.2}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+\sqrt{15.2}}{2*4}=\frac{8+\sqrt{15.2}}{8}
$